PIVector: map, reduce

rename arguments in uniform style

main.cpp

@@ -2,16 +2,22 @@
 
 
 int main(int argc, char * argv[]) {
-	PIVector<int> x(20, [](int i) {return i/2+1;});
+
+	PIVector<int> x(20, [](int i) {return i;});
 	piCout << x;
-	piCout << x.any([](int v) {return v == 20;});
+	piCout << x.any([](int v) {return v == 10;});
 	piCout << x.every([](int v) {return v > 0;});
 	piCout << x.etries([](int v) {return v % 5 == 0;});
 	piCout << x.indexWhere([](int v) {return v % 8 == 0;});
 	piCout << x.indexOf(4, -1);
 	piCout << x.lastIndexOf(1, 0);
 	piCout << x.lastIndexWhere([](int v) {return v % 8 == 0;});
-	return 0;
+	PIVector<double> x2 = x.map<double>([](int v) {return v / 10;});
+	piCout << x2;
+	piCout << x.reduce<PIString>([](int v, PIString s){return s + PIString::fromNumber(v);});
+
+	return 0; // TODO:
+
 	PIByteArray rnd;
 	rnd.resize(1024*1024, 'x'); 
 	PICLI cli(argc, argv);